如果需要将下面的json对象合并：

1. var a ={
   "a":"1","b":"2"}
2. var b ={
   "c":"3","d":"4","e":"5"}

想得到结果：

1. var c ={
   "a":"1","b":"2","c":"3","d":"4","e":"5"}

直接使用js的话，可以用一下方法：

1. <script>
2. function extend(des, src, override){
3.    if(src instanceof Array){
4.        for(var i = 0, len = src.length; i < len; i++)
5.             extend(des, src[i], override);
6.    }
7.    for( var i in src){
8.        if(override || !(i in des)){
9.            des[i] = src[i];
10.        }
11.    }
12.    return des;
13. }
14. var a ={
    "a":"1","b":"2"}
15. var b ={
    "c":"3","d":"4","e":"5"}
16. var c = extend({}, [a,b]);
17. alert(c.a);
18. </script>

当然如果你加载了jquery,那就更方便了。可以使用$.extend()方法，该方法有两种模式;

  #将后面的对象合并到新的对象中{}

  #将后面的对象合并到新的对象中{},如果深度deep为true则将递归合并成为新对象.

实例：

1. 1. <script type="text/javascript">
   2.     # 请记得先加载jquery
   3.     var a ={
      "a":"1","b":"2"}
   4.     var b ={
      "c":"3","d":"4","e":"5"}
   5.     var c = $.extend({}, a,b);
   6.     console.log(c);
   7. </script>
      如果是：
      var c = $.extend({}, [a,b]);
      -->{"0":{
      "a":"1","b":"2"},"1":{
      "c":"3","d":"4","e":"5"}}